Circuit Theory #22 | Source Transformation Method - Find V

Instructor: Dr. Süleyman Burak ÇELİK

Twenty-second lesson in the Circuit Theory series. This lesson introduces source transformation and then applies it to a worked circuit example. The goal is to find the output voltage V after converting Norton source-resistor pairs into equivalent Thevenin forms. Main ideas: - A voltage source in series with a resistor can be converted to a current source in parallel with the same resistor - A current source in parallel with a resistor can be converted to a voltage source in series with the same resistor - The resistor value stays the same during the transformation - Source polarity must follow the current-source direction Worked example: - Left transformation: `6 mA * 1.4 kOhm = 8.4 V` - Right transformation: `1 mA * 3 kOhm = 3 V` - Total series resistance: `R_T = 1.4 kOhm + 0.6 kOhm + 3 kOhm = 5 kOhm` - Net source voltage: `8.4 V - 1.4 V + 3 V = 10 V` - Loop current: `i = 10 V / 5 kOhm = 2 mA` - Final output voltage: `V = 6 V - 3 V = 3 V` Main takeaway: - Transform only strict source-resistor pairs - Keep source polarities consistent after each conversion - A correct source transformation can turn a mixed circuit into a simple series loop